X^2+241x-9972=0

Solution for X^2+241x-9972=0 equation:

X^2+241X-9972=0

a = 1; b = 241; c = -9972;
Δ = b2-4ac
Δ = 2412-4·1·(-9972)
Δ = 97969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{97969}=313$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(241)-313}{2*1}=\frac{-554}{2}
=-277
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(241)+313}{2*1}=\frac{72}{2}
=36
$